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正确制导主图：MA1:sma(c,2,1),colorgreen,linethick2;
D0 Q' x/ a7 ?1 u+ A5 h- B4 V$ iMA2:ema(c,7),colorred,linethick2;; s5 E9 G q/ y: d8 T
绿色工作线:ma1,color00ff00;3 ?5 s/ j; r) C5 D2 z
赤色机密线:ma2,color0000ff;! a3 k) t r h& b
DRAWTEXT(cross(ma1,ma2),ma1,'★买'),color0000ff;
6 Y, h3 n+ M1 P7 v- t2 U |DRAWTEXT(cross(ma2,ma1),ma1,'★跑'),color00ff00;5 w" N( M/ P9 T: ~" L% w q
mm1:=sma(c,2,1);
% u: a6 `( ?* ~6 j3 oma3:=ma(mm1,3);" C q5 n5 U9 D7 u) K2 G0 N
ss1:=cross(ma3,ma1) and ma1>ref(ma1,1) and ma1ref(v,1) and cross(c,ma1);4 a0 c; |) B" {4 u* {
Z1:=AMOUNT/V;8 h- [7 r0 J% l1 G# g3 ~) c
Z2:=L1.2;. m/ p! S8 S+ k' G1 Z
Z4:=L |
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发表于 2019-5-22 01:03:30